None of the conditions specified in that clause applies for updating key
in-place. The way I read it, a new entry is not added, so the iteration
should visit every entry only once. Thus, the program always prints "1 1".

On Tue, Aug 2, 2022 at 9:20 PM Kevin Chowski <ke...@chowski.com> wrote:

> Hello Go gurus,
>
> I think there is some ambiguity in the language spec about what happens
> when a map entry is updated during iteration. Quoting the spec (
> https://go.dev/ref/spec#For_range):
>
> 3. The iteration order over maps is not specified and is not guaranteed to
> be the same from one iteration to the next. If a map entry that has not yet
> been reached is removed during iteration, the corresponding iteration value
> will not be produced. If a map entry is created during iteration, that
> entry may be produced during the iteration or may be skipped. The choice
> may vary for each entry created and from one iteration to the next. If the
> map is nil, the number of iterations is 0.
>
> As per my read of the spec, there is no guarantee about what happens when
> you update a map key in-place.
>
> For example, is this program guaranteed to print "1 1"?
> https://go.dev/play/p/PeBEXKp1deH
>
> Apologies if I just missed some other part of the spec that ensures this.
>
> Thanks in advance for your time,
> Kevin
>
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