Cool stuff!

On Wed, Jul 27, 2022 at 3:46 PM Brian Candler <b.cand...@pobox.com> wrote:

> I see. There's a concrete benefit in using the waitgroup though: it would
> have shown you the second write blocking.
> https://go.dev/play/p/WNHRkkUUZUt
>
> On Wednesday, 27 July 2022 at 10:43:01 UTC+1 aravind...@gmail.com wrote:
>
>> Thanks Brian, Got it.
>> "A send cannot take place until the reader is ready to receive." . So an
>> unbuffered channel does not have the same behaviour as a buffered channel
>> of size 1, fair.
>>
>> I understand part about the waitGroup, I copy pasted code used to tutor
>> the newcomers to programming itself.
>>
>> On Wed, Jul 27, 2022 at 1:05 PM Brian Candler <b.ca...@pobox.com> wrote:
>>
>>> BTW, using time.Sleep() to keep goroutines running is poor practice.
>>>
>>> What I suggest is using a sync.WaitGroup.  Call wg.Add(1) for each
>>> goroutine you start; call wg.Done() when each goroutine ends; and call
>>> wg.Wait() to wait for them.
>>> https://go.dev/play/p/INl7BxG0ZSU
>>>
>>> On Wednesday, 27 July 2022 at 08:30:53 UTC+1 Brian Candler wrote:
>>>
>>>> Unless a channel is buffered, it is synchronous.  A send cannot take
>>>> place until the reader is ready to receive.
>>>>
>>>> You can make it buffered using
>>>>     numCh = make(chan int, 1)
>>>>     go write()
>>>>     go read()
>>>>
>>>> Or you can have two calls to read():
>>>>
>>>>     numCh = make(chan int)
>>>>     go write()
>>>>     go read()
>>>>     go read()
>>>>
>>>> On Wednesday, 27 July 2022 at 08:13:34 UTC+1 aravind...@gmail.com
>>>> wrote:
>>>>
>>>>> Hi All,
>>>>> When I was explaining basics of channels to newcomers, I was using the
>>>>> below example
>>>>> https://go.dev/play/p/xx2qqU2qqyp
>>>>>
>>>>> I was expecting both Write 5 and Write 3 to be printed. But only Write
>>>>> 5 was printed. I couldn't reason out the behaviour, can somebody point out
>>>>> what I am assuming wrong about.
>>>>>
>>>>> Thanks,
>>>>> Aravindhan K
>>>>>
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