You did not close ch2 in the first goroutine. Therefore, the second
goroutine never reaches line "ch <- struct{}{}"
Aleksei Perevozov
воскресенье, 5 июня 2022 г. в 16:06:53 UTC+2, manjee...@gmail.com:
> I just started to learn Go Language, and I'm enjoying writing code in Go.
> So today, I'm trying to understand how the unbuffered channel works
>
> Can someone help me to understand why this code is not working. I'm
> expecting that <-ch wait until we receive from channel ch
>
>
> func main() {
> ch := make(chan struct{})
> ch2 := make(chan int)
>
> go func() {
> arr := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
> for _, v := range arr {
> ch2 <- v
> }
> }()
>
> go func() {
> for t := range ch2 {
> fmt.Println(t)
> }
> ch <- struct{}{}
> }()
>
> <-ch
> }
>
> Thanks & Regards
>
> Manjeet Thakur
>
>
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