2 options: put a timeout on the listen and loop. Close the socket it is
listening on.
> On Apr 16, 2022, at 8:30 AM, Zhaoxun Yan <yan.zhao...@gmail.com> wrote:
>
>
> Timeout is quite common practice in programming. For example, Listen
> function in internet connection with a timeout may just close the connection
> and Listen thread as silence persists for some period, like 60 seconds.
>
> I found it very hard to implement such a general shutdown feature of a
> thread/goroutine on such I/O functions, here is one unsuccessful try, which I
> want to stop the whole in 9 seconds but it does not function as I wanted:
>
> package main
>
> import (
> "fmt"
> "time"
> )
>
> func wait(){
> time.Sleep(5 * time.Second)
> fmt.Println("wait 1st signal")
> time.Sleep(5 * time.Second)
> fmt.Println("wait 2nd signal")
> }
>
>
> func main() {
> ticker := time.NewTicker(3 * time.Second)
> i := 0
> for{
> select{
> case <- ticker.C:
> i++
> fmt.Printf("ticker rings %d\n", i)
> if i==3{
> return
> }
> default:
> wait()
> }
> }
>
> }
>
> The result is to wait whole 30 seconds:
> wait 1st signal
> wait 2nd signal
> ticker rings 1
> wait 1st signal
> wait 2nd signal
> ticker rings 2
> wait 1st signal
> wait 2nd signal
> ticker rings 3
>
> An online course suggests to wrap up the wait/Listen function with a channel
> (which would return something instead of nothing above)
>
> go func(){
> resultChan <- Listen()
> }()
>
> select{
> case a := <- resultChan:
> //analyze a
> case <-ticker.C:
> //might break or return
> }
>
> But this recipe obviously only kill the select goroutine rather than the
> anonymous goroutine that actually runs Listen function. My question is - how
> to kill the waiting or listening goroutine from outside?
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