On Sun, Apr 3, 2022 at 3:07 PM Ramil M <mirhasa...@gmail.com> wrote:
>
> I am sorry, I may have not made myself clear earlier. This code is valid and 
> actually works fine for me.
> I was just thinking that this particular example is very specific, where you 
> manipulate with bash, so that it forwards stdout to stderr in it's second 
> command(echo 1>&2 stderr).
> So in this case we actually are not getting an *exec.ExitError when we run 
> the code, but forwarded stderr output by shell instead.
> If for instance we run any other command in bash, that will fail and output 
> to stderr, the original example will break and exit with log.Fatal(err).
> So I was wondering if  rewiring the example will be accepted by the go 
> community.

Sorry for misunderstanding.

The idea of the example is that we write some text to stdout, and
write some text to stderr, and the CombinedOutput method returns both.
It's just intended to show what the CombinedOutput method does.  I'm
not sure your suggested change makes that clearer.

Ian



> On Sunday, April 3, 2022 at 10:15:17 PM UTC+3 Brian Candler wrote:
>>
>> On Sunday, 3 April 2022 at 16:49:30 UTC+1 mirha...@gmail.com wrote:
>>>
>>> CombinedOutput example listed above will always print only stdout, but not 
>>> combined stdout and stderr as intended to be shown in the example.
>>
>>
>> Works for me (macOS 10.12, go 1.18)
>>
>> If this doesn't work for you, it could be that the 'sh' on your system isn't 
>> a POSIX-compatible shell.  What happens if you change 'sh' to 'bash'?
>>
>> If it still doesn't work, can you say some more about the system you're 
>> running on? Is it anything Windows-based (e.g. WSL or Cygwin?)
>
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