Because the arguments are evaluated when the go keyword is encountered - and
listen and serve is blocking on port 8082
> On Feb 18, 2022, at 10:38 AM, Christoph Berger <christoph.g.ber...@gmail.com>
> wrote:
>
>
> Hi gophers,
>
> I hope someone can help finding out why a particular goroutine call can block
> the main goroutine.
>
> In the following code, all "go" calls spawn off a goroutine and return as
> expected, except for the last one that blocks the main goroutine.
>
> Is this a bug, or am I missing something subtle or even obvious (obvious to
> all others only of course)?
>
> package main
>
> import (
> "log"
> "net/http"
> )
>
> func main() {
> // all of these work as expected
> go http.ListenAndServe("localhost:8080", nil)
> go log.Println("goroutine")
> go func() {
> log.Println(http.ListenAndServe("localhost:8081", nil))
> }()
>
> // The following line blocks the main goroutine.
> go log.Println(http.ListenAndServe("localhost:8082", nil))
>
> log.Println("after go log.Println(http.ListenAndServe())") // never
> prints
> select {} // remove this, and the code still never finishes
> }
>
> All three servers eventually run (try curl localhost:8080; curl
> localhost:8081; curl localhost:8082),
>
> In the playground, the code even deadlocks.
>
> Any idea?
>
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