Thanks for the response Ian.
This makes so much sense now.
On the back of this I have yet another (probably stupid) question - about
the type inference at compile time.
Suppose we have a type
type stateFunc[T any] func(T) stateFunc[T]
and a function
func someFunc(înput int) stateFunc[int] {...}
and do something like this for interface compliance checks at compile time
var _ stateFunc = someFunc
Shouldn't the compiler already be able to infer that stateFunc type
parameter is int?
On Thursday, 17 February 2022 at 00:49:32 UTC Ian Lance Taylor wrote:
> On Wed, Feb 16, 2022 at 4:22 PM Tajmeet Singh <tjgur...@gmail.com> wrote:
> >
> > I have been experimenting with the generics code for a bit and I came
> across a situation here I wanted to use a generic func as a type
> >
> > Consider the following:
> >
> > I have a few sort functions which I want to use for testing and
> profiling, for this I use something like this
> >
> > var sortFuncs = []struct {
> > name string
> > sFunc func([]int)
> > }{
> > {
> > name: "Quick Sort",
> > sFunc: sort.Quick,
> > },
> > }
> >
> > Now this sFun inside the struct expects a function with signature
> func([]nit)
> >
> > Consider further that we have made changes to these sort functions and
> now their signature is something like this
> >
> > func Quick[T constraints.Ordered](arr []T)
> >
> > How do I make changes to this anonymous struct and sFunc so that they
> use the new generic func signature?
>
> Type parameters are associated with type names. So you would have to
> give the anonymous struct a name.
>
> But that doesn't seem likely to help you. A variable can not have
> type parameters. Your variable sortFuncs has to be a slice of some
> specific instance of the anonymous struct. Given that, you may as
> well sortFuncs the same and write "sfunc: sort.Quick[int]".
>
> Ian
>
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