Yes.
1. `counter++` happens-before `ch <- struct{}{}`, because in a single
goroutine, happens-before is equivalent with lexical statement order
2. `ch <- struct{}{}` happens-before `<-ch` completes, because "A send on a
channel happens before the corresponding receive from that channel
completes".
3. `<-ch` completion happens-before `fmt.Println(counter)`, again because
in a single goroutine, happens-before is equivalent with lexical statement
order
Therefore, `counter++` happens-before `fmt.Println(counter)`.
On Mon, Feb 1, 2021 at 4:06 PM xie cui <cuiwei...@gmail.com> wrote:
> here is the code:
> package main
>
> import "fmt"
>
> func main() {
> counter := 0
> ch := make(chan struct{}, 1)
> closeCh := make(chan struct{})
> go func() {
> counter++ //(1)
> ch <- struct{}{}
> }()
> go func() {
> _ = <-ch
> fmt.Println(counter) //(2)
> close(closeCh)
> }()
> _ =<-closeCh
> }
>
> is (1) happens before (2)? why?
>
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