By ‘at the same time’ I would understand that none of them are able to see the counter in the wait group after one member had triggered release.
That is, I believed that “release by any go routine (that is, a Wait() done by any collaborating goroutine which saw a zero counter) " happened before "any go routine did anything else beyond returning from Wait()” If that were the case, none of them would ever see a non-zero count after any one of them had seen it, and so no race condition could exist You suggest that that is not the case. (I don’t intend to be obtuse, even if I seem so) — P > On Jan 16, 2021, at 8:38 PM, Robert Engels <reng...@ix.netcom.com> wrote: > > It does release them all at once. They all become ready to run at the “same > time” - the scheduler has to get them to run. Even if the release was atomic > it would make no difference in the race condition. > >> On Jan 16, 2021, at 7:35 PM, Pete Wilson <peter.wil...@bsc.es> wrote: >> >> WARNING / LEGAL TEXT: This message is intended only for the use of the individual or entity to which it is addressed and may contain information which is privileged, confidential, proprietary, or exempt from disclosure under applicable law. If you are not the intended recipient or the person responsible for delivering the message to the intended recipient, you are strictly prohibited from disclosing, distributing, copying, or in any way using this message. If you have received this communication in error, please notify the sender and destroy and delete any copies you may have received. http://www.bsc.es/disclaimer http://bsc.es/disclaimer -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/2C9CDF2C-4484-4E0F-870E-FB285B46E9FF%40bsc.es.
