On Thu, Jul 23, 2020 at 5:27 PM Robert Solomon <drrob...@gmail.com> wrote:
>
> Hi. I'm going thru the example code for container/heap. In the
> documentation is this example:
>
> func (h *IntHeap) Pop() interface{} {
> old := *h
> n := len(old)
> x := old[n-1]
> *h = old[0 : n-1] // my question is about this line.
> return x
> }
>
> Why does the last assignment have to assign to a dereferenced pointer, ie, *h
> = old[0 : n-1]?
> Why does it not work if the last assignment is written as old = old[0 : n-1]?
> I know this does not work because I tried it.
I'm not quite sure how to answer this question because there seems to
be some sort of deep misunderstanding here.
"old" is a local variable in the IntHeap.Pop method. Changing old, as
with "old = old[0 : n-1]", isn't going to affect the heap at all. It
will just change a local variable that will go away when the method
returns.
Ian
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