Ok, you are right. But I was confused with this: 2009/11/10 23:00:00 -----------------Start 2009/11/10 23:00:00 Sleeping 8 seconds..2009/11/10 23:00:03 Canceling doWork goroutine reach 3s...2009/11/10 23:00:08 Done sleeping! 2009/11/10 23:00:08 doWork exited. 2009/11/10 23:00:08 Done. 2009/11/10 23:00:08 -----------------End My previous questions were: How can I cancel execution of goToSleep() function? How can I break it? Because I expect code to stop function gotoTosleep() at 3s, but I saw still running at 8s because prints "Done sleeping!"..
But Michael Levieux got the idea and repliedr:"You cannot terminate a function execution from its caller.." . So I was wrong in my understanding how to implement "cancel" or "break" goroutinea. El martes, 25 de febrero de 2020, 13:45:03 (UTC-3), Jake Montgomery escribió: > > Expected behaviour is to end anonyimous func when 3s timeout is reached. >> > > So what is the problem? The whole thing *does *exit after 3 seconds. Of > course, your main() is a loop, so it starts again. > > 2009/11/10 23:00:00 -----------------Start > 2009/11/10 23:00:03 Canceling doWork goroutine reach 3s... > 2009/11/10 23:00:03 doWork exited. > 2009/11/10 23:00:03 Done. > 2009/11/10 23:00:03 -----------------End > > > What exactly did you expect to see other than that? > > On Monday, February 24, 2020 at 6:45:26 PM UTC-5, Juan Mamani wrote: >> >> Sorry again. Well, I followed your advice. Here is the link >> https://play.golang.org/p/7DigEVsKbdx >> How can I cancel goToSleep() when timeout is reached? >> >> >> El lunes, 24 de febrero de 2020, 14:16:32 (UTC-3), Jake Montgomery >> escribió: >>> >>> Your code will still not compile. In this group, it is often helpful to >>> include a link to your code in the playground (https://play.golang.org/) >>> using the "Share" button. That is in addition to, or instead of, posting >>> your code in the message. This will allow others to easily run your code, >>> but also will allow you to make sure it compiles. >>> >>> On Monday, February 24, 2020 at 10:01:01 AM UTC-5, Juan Mamani wrote: >>>> >>>> Sorry}, here is the right code: ( just was the effect to b working til >>>> At 5:20am sleepy and lost) >>>> >>>> Expected behaviour is to end anonyimous func when 3s timeout is >>>> reached. >>>> >>>> //------------------------------------------------ >>>> package main >>>> >>>> import( >>>> //"fmt" >>>> "time" >>>> "math/rand" >>>> "log" >>>> ) >>>> >>>> func main(){ >>>> >>>> for{ >>>> log.Println("-----------------Start") >>>> Task() >>>> log.Println("-----------------End") >>>> >>>> } >>>> >>>> } >>>> >>>> >>>> // Trying to adapt from Concurrency in Go by Katherine Cox-Buday >>>> func Task(){ >>>> >>>> doWork := func( done <-chan interface{}, strings <-chan string, ) >>>> <-chan interface{} { //1 >>>> terminated := make(chan interface{}) >>>> go func() { >>>> defer log.Println("doWork exited.") >>>> defer close(terminated) >>>> for { >>>> goToSleep() >>>> select { >>>> //case s := <-strings: >>>> // case s := ran(): >>>> // Do something interesting >>>> //fmt.Println(s) >>>> case <-done: //2 >>>> return >>>> } >>>> } >>>> }() >>>> return terminated >>>> } >>>> >>>> done := make(chan interface{}) >>>> terminated := doWork(done, nil) >>>> >>>> go func() { //3 >>>> // Cancel the operation after 3 second. >>>> time.Sleep(3 * time.Second) >>>> log.Println("Canceling doWork goroutine reach 3s...") >>>> close(done) >>>> }() >>>> >>>> <-terminated //4 >>>> log.Println("Done.") >>>> } >>>> >>>> done := make(chan interface{}) >>>> terminated := doWork(done, nil) >>>> >>>> go func() { //3 >>>> // Cancel the operation after 3 second. >>>> time.Sleep(3 * time.Second) >>>> log.Println("Canceling doWork goroutine reach 3s...") >>>> close(done) >>>> }() >>>> >>>> <-terminated //4 >>>> log.Println("Done.") >>>> } >>>> >>>> >>>> >>>> func goToSleep(){ >>>> >>>> >>>> >>>> >>>> >>>> >>>> rand.Seed(time.Now().UnixNano()) >>>> n := rand.Intn(12) // n will be between 0 and 10 >>>> log.Println("Sleeping ",n,"seconds..") >>>> time.Sleep(time.Duration(n)*time.Second) >>>> log.Println("Done sleeping!") >>>> } >>>> >>>> //------------------------------------------------ >>>> >>>> >>>> >>>> El lunes, 24 de febrero de 2020, 6:09:09 (UTC-3), Lutz Horn escribió: >>>>> >>>>> > I've tried to adapt from from "Concurrency in Go by Katherine >>>>> Cox-Buday" to >>>>> > understand how to apply timeout. But I don't get it. >>>>> >>>>> What are you trying to do? What is the expected behaviour, what >>>>> happens instead? >>>>> >>>>> BTW, this code does not compile, there are same unbalanced curly >>>>> brackets. >>>>> >>>>> Lutz >>>>> >>>> -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/89505008-1f6b-4635-be50-7d3c64b9dd05%40googlegroups.com.
