Thank you, it is clear now. On Tue, Jan 7, 2020 at 11:10 AM Ian Lance Taylor <i...@golang.org> wrote:
> On Mon, Jan 6, 2020 at 9:18 PM Prabhu Chawandi <prabhuchawa...@gmail.com> > wrote: > > > > I was reading this article @ > https://blog.golang.org/laws-of-reflection > > > > Excerpt: > > > > One important detail is that the pair inside an interface always has the > form (value, concrete type) and cannot have the form (value, interface > type). Interfaces do not hold interface values. > > > > I could not understand it clearly, Can through some clarity with an > example? > > > > I tried this and did not give any error. > > > > @ https://play.golang.org/p/Q5jRWp6MF7c > > Interfaces do not hold interface values. > > What this means is that when you write "a = b" where a and b are both > of interface type, then the value that is in b will be copied to a. a > will wind up with the dynamic type and dynamic value that were > originally in b. The dynamic type of a will not become the type of b; > it will become the dynamic type of the value stored in b. > > Ian > -- Cheers p. -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/CAN9r%3DsyFvWiYGf0m%2BaT6By4VhO_cGH0-V0vs%3DaffCFHfLm1ZtA%40mail.gmail.com.
