I don't know of any primitives that would return the current processor the
goroutine is currently running on. Maybe if you explain more precisely what
you are trying to do, we can find a better solution?
@lgodio2 no, as Jan said, the go statement is not an expression, so you
can't assign with it, you need to do either:
func main() {
var s1 TYPE
go func () {
s1 = f1()
}
s2 := f2()
}
OR
func main() {
var s1 TYPE
var s2 TYPE
go func () {
s1 = f1()
}()
go func() {
s2 = f2()
}()
}
However in the second solution, if you execute that in the main goroutine
or if you need those two assignments to be done before doing something
else, you might want to use synchronisation primitives such as waitgroups.
Le mar. 7 mai 2019 à 07:51, Nitish Saboo <nitish.sabo...@gmail.com> a
écrit :
> Hi Michel,
>
> Yes, this is what I was looking for.Thankyou..:)
>
> Can we also find the processor on which this go routine is running?
>
> Thanks
>
>
> On Mon, 6 May 2019, 17:43 Michel Levieux, <m.levi...@capitaldata.fr>
> wrote:
>
>> Hello,
>>
>> Is:
>>
>> type Y struct {
>>
>> M string
>> N string
>>
>> }
>>
>> func initalize() Y{
>> // I have a func that return an object ob type Y.
>> }
>>
>> var obj1 Y
>> go func() {
>> obj1 = initalize()
>> }()
>>
>> var obj2 Y
>> go func() {
>> obj2 = initalize()
>> }()
>>
>> What you are looking for?
>>
>> Le lun. 6 mai 2019 à 13:59, Jan Mercl <0xj...@gmail.com> a écrit :
>>
>>> On Mon, May 6, 2019 at 1:39 PM Nitish Saboo <nitish.sabo...@gmail.com>
>>> wrote:
>>>
>>> > type Y struct {
>>> >
>>> > M string
>>> > N string
>>> >
>>> > }
>>> >
>>> > func initalize() Y{
>>> > // I have a func that return an object ob type Y.
>>> > }
>>> > var obj1 Y = go initalize()
>>>
>>> No need to write Y above, the type will be inferred. However, see
>>> https://golang.org/ref/spec#Go_statements The go statement is not an
>>> expression while the `var foo = expr` requires an expression.
>>>
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