To a first order approximation, there is no guarantee of events between any
two go processes. The scheduler is free to chose any unblocked process.
Here's what I think is happening.
go sync () // creates the sync routine
fmt.Println("0") // prints
time.Sleep(time.Second) // sends this routine to sleep
// scheduler looks for work
fmt.Println("1")
time.Sleep(time.Second) // sends the other routine to sleep
// scheduler now has 2 routines waiting for a second to elapse
// sufficient timer ticks elapse for a second to be counted as passing
// both routines "unsleep" and are marked as being able to be scheduled
// scheduler looks for something to do
// may pick either routine, probably sensible though to go back to the last
routine that did work
// (cache locality and all that)
fmt.Println("3")
time.Sleep(time.Second)
// scheduler looks for work
fmt.Println("2")
Again once you have work in the queue, the scheduler is free to schedule
work from that queue in any order. The timer tick will probably (but not
certainly) mean that both these routines unblock concurrently and so are on
the work queue at the same moment.
Unless I am much mistaken the scheduler is architecturally free to swap
between active routines at any time. I believe the current design will
normally only evaluate the swap (cooperatively multi-task) on function
calls (I could be mis-remembering this though).
HTH
Chris
On Monday, 8 April 2019 14:38:40 UTC+1, go je wrote:
>
> ascending only work if i cut the first sleep half second to print them
> alternately but isn't they sequentially running?
>
> On Mon, Apr 8, 2019 at 9:30 PM go je <laure...@gmail.com <javascript:>>
> wrote:
>
>> https://play.golang.org/p/0TIxVFuqGoB
>>
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>
>
> lol
>
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