Then rewrite it this way
func SomeFunc() { count:= 1 p := &count total := 0 for i:=0;i<100000;i++ { total = total + *p someOtherFunc() } } it should definitely be optimized away in this case. > On Nov 30, 2018, at 12:09 PM, Jakob Borg <ja...@kastelo.net> wrote: > > This should only be valid for a loop that doesn’t include any function calls, > or if the compiler can prove that said function calls don’t involve any > synchronization primitives anywhere in the possible call stack. > > So maybe it’s optimized in > > for … { > total += *p > } > > but I wouldn’t bet on it in > > for … { > total += *p > foo() > } > > //jb > >> On 30 Nov 2018, at 19:01, robert engels <reng...@ix.netcom.com >> <mailto:reng...@ix.netcom.com>> wrote: >> >> I would think the compiler would be free to optimize this as a single load >> outside the loop - as Go has no volatile declaration (to inform the compiler >> that some other thread might of changed the value of *p) >> >>> On Nov 30, 2018, at 11:58 AM, robert engels <reng...@ix.netcom.com >>> <mailto:reng...@ix.netcom.com>> wrote: >>> >>> It’s as simple as: >>> >>> var count = 1 >>> var p = &count >>> >>> func X() { >>> total :=0 >>> >>> for i:=0; i <1000000;i++ { >>> total = total + *p >>> } >>> } >>> >>> no ? >>> >>>> On Nov 30, 2018, at 11:48 AM, Mark Volkmann <r.mark.volkm...@gmail.com >>>> <mailto:r.mark.volkm...@gmail.com>> wrote: >>>> >>>> I think I failed to come up with a good code example. But suppose I need >>>> to do something with a pointer inside a loop that really does require >>>> dereferencing it and the pointer never changes inside the loop. In that >>>> case will the Go compiler optimize that so the dereference doesn't happen >>>> in each loop iteration? >>>> >>>> On Fri, Nov 30, 2018 at 11:36 AM Jan Mercl <0xj...@gmail.com >>>> <mailto:0xj...@gmail.com>> wrote: >>>> >>>> On Fri, Nov 30, 2018 at 6:16 PM Mark Volkmann <r.mark.volkm...@gmail.com >>>> <mailto:r.mark.volkm...@gmail.com>> wrote: >>>> >>>> > Will the Go compiler optimize the pointer dereference so it doesn't >>>> > happen in every loop iteration? If not, is it common practice to do that >>>> > outside the loop like this? >>>> > >>>> > myValue := *myPtr >>>> > for _, v := range values { >>>> > fmt.Printf("%v %v\n", myValue, v) >>>> > } >>>> >>>> There's no pointer dereference inside the loop. But there's an allocation >>>> inside the loop, on every iteration, that puts a pointer to a copy of >>>> myValue into an interface{} that's passed to fmt.Printf. The allocation >>>> can be probably avoided: >>>> >>>> myValue := interface{}(*myPtr) >>>> for _, v := range values { >>>> fmt.Printf("%v %v\n", myValue, v) >>>> } >>>> >>>> But the %v verb handle pointers in many cases well. If that holds for the >>>> type of *myPtr then simply: >>>> >>>> for _, v := range values { >>>> fmt.Printf("%v %v\n", myPtr, v) >>>> } >>>> >>>> is what could be good enough. >>>> >>>> -- >>>> -j >>>> >>>> >>>> >>>> -- >>>> R. Mark Volkmann >>>> Object Computing, Inc. >>>> >>>> -- >>>> You received this message because you are subscribed to the Google Groups >>>> "golang-nuts" group. >>>> To unsubscribe from this group and stop receiving emails from it, send an >>>> email to golang-nuts+unsubscr...@googlegroups.com >>>> <mailto:golang-nuts+unsubscr...@googlegroups.com>. >>>> For more options, visit https://groups.google.com/d/optout >>>> <https://groups.google.com/d/optout>. >>> >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "golang-nuts" group. >>> To unsubscribe from this group and stop receiving emails from it, send an >>> email to golang-nuts+unsubscr...@googlegroups.com >>> <mailto:golang-nuts+unsubscr...@googlegroups.com>. >>> For more options, visit https://groups.google.com/d/optout >>> <https://groups.google.com/d/optout>. >> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "golang-nuts" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to golang-nuts+unsubscr...@googlegroups.com >> <mailto:golang-nuts+unsubscr...@googlegroups.com>. >> For more options, visit https://groups.google.com/d/optout >> <https://groups.google.com/d/optout>. > > > -- > You received this message because you are subscribed to the Google Groups > "golang-nuts" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to golang-nuts+unsubscr...@googlegroups.com > <mailto:golang-nuts+unsubscr...@googlegroups.com>. > For more options, visit https://groups.google.com/d/optout > <https://groups.google.com/d/optout>. -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.