Please create a test case (snooth_test.go) which illustrates your problem: 
has the input as const string, tries to Unmarshal into your chosen struct, 
probably fails with error.
All without making HTTP requests!


2018. május 14., hétfő 14:29:57 UTC+2 időpontban Luke IC a következőt írta:
>
> I've tried that, but I need to decode the JSON into a struct generated 
> from a .proto. Updating the code to use json.Unmarshal results in the 
> wines array from the response not decoding correctly, here is what I see 
> when printing the struct that I have unmarshalled into: 
> meta:<results:1489449 returned:15 status:1 > wines:<> wines:<> wines:<> 
> wines:<> wines:<> wines:<> wines:<> wines:<> wines:<> wines:<> wines:<> 
> wines:<> wines:<> wines:<> wines:<> 
>
> Note the repeated values are empty. The relevant source code can be viewed 
> here: https://github.com/lukeic/vinogo/tree/feature/snooth/snooth 
> <https://www.google.com/url?q=https%3A%2F%2Fgithub.com%2Flukeic%2Fvinogo%2Ftree%2Ffeature%2Fsnooth%2Fsnooth&sa=D&sntz=1&usg=AFQjCNFw1bOg4tMyH2nskcS46qw_S9Yusg>.
>  
> Help figuring this out would be much appreciated as I've spent ages on it 
> now.
>
>
> On Monday, 14 May 2018 17:46:58 UTC+10, Tamás Gulácsi wrote:
>>
>> It DOES parse with then encoding/json package: 
>> https://play.golang.org/p/IQzMm2tDI7w
>>
>> The protoc-generated code's Unmarshal parses a *Protocol Buffers* 
>> encoded byte stream, NOT JSON!
>>
>>
>> 2018. május 14., hétfő 5:24:06 UTC+2 időpontban Luke IC a következőt írta:
>>>
>>> Hi all,
>>>
>>> I'm creating a microservice in Go, using protocol buffers and gRPC. It 
>>> interacts with a third-party API (Snooth) and I'm trying to unmarshal the 
>>> JSON response into a protobuf struct I've created, using the proto 
>>> package.
>>>
>>> Unmarshalling returns an unexpected EOF error.
>>>
>>>
>>> I've summed up the details in full on this question at Stack Overflow: 
>>> https://stackoverflow.com/questions/50314476/why-does-unmarshalling-this-api-response-return-an-unexpected-eof
>>>
>>>
>>> In addition to the information posted there, I've also tried using 
>>> strconv.Unquote before unmarshalling in line with the idea that the escaped 
>>> characters in the API response are causing a double-encode. But this didn't 
>>> work either.
>>>
>>> Any help would be greatly appreciated as I've been stuck on this for a 
>>> while now and feel there's something simple I'm missing.
>>>
>>>
>>> Thanks.
>>>
>>

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