I think the answer is probably the simpler one. Go seems to be checking "Is this expression composed of Go official instructions and libs or is it a user-defined construct?"
Maybe it is just discarding user-defined functions because it doesn't know if the function return value may change during the program execution. Just to be on the safe side. []'s Ailton 2018-03-29 14:13 GMT-03:00 Nilsocket <nilsoc...@gmail.com>: > > > https://research.swtch.com/godata >> > I did read it, but what I was asking is irrelevent to it. > > func showInt(x int) { > res := (*[unsafe.Sizeof(x)]byte)(unsafe.Pointer(&x)) > for i := range res { > fmt.Printf("%.2x ", res[i]) > } > fmt.Println() > } > // showInt(12345) > // 39 30 00 00 00 00 00 00 > > An integer in it's binary form is stored like above, little endian. > What I mean is how, strings are represented, while converting a string to > []byte, gives me utf-8 values, > but directly ascessing the underlying memory of string, without converting > it to []byte shows different things. > > > > >> > Because in Go the size of an array must be a constant. >> > >> > Ian >> > > > An array size must be constant, but my real question is? > How come, a uintptr type value returned by unsafe.Sizeof(x), is considered > as const? > and doesn't accept, if uintptr type value is returned by someother > function. > I mean, how was it able to differentiate between someother function and > unsafe.Sizeof(x). > > -- > You received this message because you are subscribed to the Google Groups > "golang-nuts" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to golang-nuts+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/d/optout. > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
