Hi. Don't worry, I do get pointers and pass-by-value.
I expected the expression (*x) to yield a copy to the pointed-to value.
But, as you say, that happens on assignment.
On Wednesday, March 28, 2018 at 6:50:06 PM UTC+2, Devon H. O'Dell wrote:
>
> 2018-03-28 9:39 GMT-07:00 Devon H. O'Dell <devon...@gmail.com
> <javascript:>>:
> > CopyExplicitDeref gets a pointer to the struct in its receiver. If you
> > have a pointer to T, then taking a pointer to the dereferenced T is a
> > no-op: you get the pointer of the thing you just dereferenced. Any
> > statement &*whatever will always yield the value of whatever. Copy
> > happens on assignment, and no assignment occurs in this statement.
>
> I just realized that one additional thing that might be confusing is
> that you're expecting CopyExplicitDeref to get a copy of _something_
> since everything in Go is done by-value. Indeed, CopyExplicitDeref
> does get a copy of something: the pointer to T. So if you change
> CopyExplicitDeref to:
>
> func (t *T) CopyExplicitDeref() **T {
> return &t
> }
>
> and in main:
>
> a := &T{0}
> b := a.CopyExplicitDeref()
> fmt.Println(&a == b)
>
> you will see that it's actually the pointer that is copied.
>
> --dho
>
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