I'm far from the expert on the spec but the behavior seems to follow the rules.
https://golang.org/ref/spec#Arithmetic_operators "Arithmetic operators apply to numeric values and yield a result of the same type as the first operand." myInt + myInt returns myInt because it's the type of first operand. Is myInt a "numeric value"? https://golang.org/ref/spec#Type_declarations "A type definition creates a new, distinct type with the same underlying type <https://golang.org/ref/spec#Types> and operations as the given type, and binds an identifier to it." myInt is a distinct type from int, but it has the same underlying type and is therefore "numeric value". On Sunday, February 18, 2018 at 11:30:58 AM UTC-8, Bill Wood wrote: > > Thanks. Why is the plus operator defined on myInt? Or if it simply > treats a myInt as an int, why isn't the result an int? > > Sorry if this is a stupid question; I think either there is something > deeper to this or else the arithmetic operators just have a special > processing for this case. > > On Sunday, February 18, 2018 at 2:16:17 PM UTC-5, Jan Mercl wrote: >> >> On Sun, Feb 18, 2018 at 8:06 PM Bill Wood <wpwo...@gmail.com> wrote: >> >> > I thought that the plus operator would return an int, not a myInt. >> >> expr1 + expr2 works iff types of expr1 and expr2 are the same and the >> result has the same type as both of the operands. Analogically for the >> subtraction, multiplication and division operations. >> >> -- >> >> -j >> > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
