On Sun, Feb 11, 2018 at 7:27 AM, rajesh nataraja <rnatar...@gmail.com>
wrote:
> Compiler does not allow this, aren't they essentially all the same? What
> is the reason this is not allowed?
>
Go is strictly typed. As such, it limits conversions (much more automatic
ones) between types that are not the same.
Types are characterized by two things: The data they hold and the
operations you can do on them. The latter is, what you usually declare new
types for. So, for examples, if I do
type F struct{
*bytes.Buffer
}
then an F is basically the same as a *bytes.Buffer - they have the same
representation in memory. But I can then do
func (f F) Write(p []byte) (n int, err error) {
n, err = f.Buffer.Write(p)
if err != nil {
log.Printf("Error writing to buffer: %v", err)
}
return n, err
}
thus modifying the behavior of the type.
Different type-declarations usually imply different operations on the same
underlying data. In your case, it only makes sense to declare both T1 and
T2, if they are supposed to do different things, even if they have the same
structure. Different method-sets will usually use and enforce different
invariants, so there are usually severe problems with intermixing them.
So if what you want would be allowed - transparently converting between
values with the same representation - that would essentially negate most of
the point of the type-checker. By declaring two types you are explicitly
stating, that you want them to be treated as different and Go's strict
typing makes sure that you do.
> Thanks
> Rajesh.
>
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