It's in the spec under constants: arithmetic has arbitrary precision. When you restrict to a floating point type by assigning to a variable you also restrict the precision of the result.
On Thu, Nov 9, 2017, 4:35 PM <eriksro...@gmail.com> wrote: > Why are the following unequal in Go? Is this a bug, or is it by design? If > it's by design, why does this occur and is this type of behavior documented > anywhere? > > https://play.golang.org/p/itEV9zwV2a > > package main > > import ( > "fmt" > ) > > func main() { > x := 10.1 > > fmt.Println("x == 10.1: ", x == 10.1) > fmt.Println("x*3.0 == 10.1*3.0:", x*3.0 == 10.1*3.0) > fmt.Println("x*3.0: ", x*3.0) > fmt.Println("10.1*3.0: ", 10.1*3.0) > } > > Produces: > > x == 10.1: true > x*3.0 == 10.1*3.0: false > x*3.0: 30.299999999999997 > 10.1*3.0: 30.3 > > > -- > You received this message because you are subscribed to the Google Groups > "golang-nuts" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to golang-nuts+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/d/optout. > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
