Thanks for the reply How to gather all the values into CH and return to print
Thanks On Wednesday, October 25, 2017 at 7:41:34 PM UTC+5:30, M. Shulhan wrote: > > On Wed, 25 Oct 2017 06:30:09 -0700 (PDT) > desaia...@gmail.com <javascript:> wrote: > > > I am expecting to show url1 (2 sec ), url2 (4 sec ) but not url3( 6 > > sec) where timeout is 5 sec > > > > but program showing only url1 value > > > > Please help > > > > https://play.golang.org/p/aMOoSEHjmZ > > > > Thanks in advance > > > > Rgds, > > > > Abhi > > > > > > package main > > > > import "fmt" > > import "time" > > > > func InvokeUrl1(u string, val chan<- string) { > > time.Sleep(2 * time.Second) > > val <- "Url1 Value" > > } > > func InvokeUrl2(u string, val chan<- string) { > > time.Sleep(4 * time.Second) > > val <- "Url2 Value" > > } > > func InvokeUrl3(u string, val chan<- string) { > > time.Sleep(6 * time.Second) > > val <- "Url3 Value" > > } > > > > func GetUrlValues(urls []string) { > > > > ch := make(chan string, 1) > > for _, url := range urls { > > go func(u string) { > > val := make(chan string) > > if u == "url1" { > > go InvokeUrl1(u, val) > > } else if u == "url2" { > > go InvokeUrl2(u, val) > > } else if u == "url3" { > > go InvokeUrl3(u, val) > > } > > > > select { > > case ret := <-val: > > ch <- ret > > case <-time.After(5 * time.Second): > > ch <- "nil" > > } > > }(url) > > } > > fmt.Println(<-ch) > > You only print once, it suppose to be inside the loop or wrapped with > select while <-ch != "nil". > > > } > > func main() { > > GetUrlValues([]string{"url1", "url2", "url3"}) > > } > > > > > > -- > { "name":"Mhd Sulhan", "phone":"+628567826625", "site":"kilabit.info" } > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
