On Wed, Jul 19, 2017 at 4:10 PM,  <adrian.pr...@gmail.com> wrote:
>
> The EBNF specifies the syntax, not the behavior. EBNF does not indicate the
> order of evaluation of source code, only the order of characters in the
> source code.

Fair point.  In this case it is also intended to indicate the
precedence.  In fact, in every case I know of, it indicates the
precedence.

Ian

> On Wednesday, July 19, 2017 at 6:59:29 PM UTC-4, Ian Lance Taylor wrote:
>>
>> On Wed, Jul 19, 2017 at 3:28 PM,  <adrian...@gmail.com> wrote:
>> >
>> > A question on Stack Overflow led me to carefully examine the spec and I
>> > feel like there may be some detail that's missing - the behavior is easy
>> > enough to work with, but it's effectively undefined according to the
>> > language spec. Specifically, with a variable x of type *[]string for
>> > example, *x[0] will not work because it is evaluated as *(x[0]), not as
>> > (*x)[0]. This is unexpected based on the spec because the only
>> > specifications that could apply are the general order of evaluation, which
>> > is left to right (not the case here), and operator precedence which states
>> > that pointer dereference is a unary operator and unary operators have
>> > highest precedence (again clearly not what's happening).
>> >
>> > The closest it comes to explaining this behavior is in the section on
>> > address operators, which implies that the address operator & applies to the
>> > entire slice expression next to it (or struct field selector, etc). This
>> > leaves one to assume the same implication applies to the pointer 
>> > dereference
>> > operator as well.
>> >
>> > Is there something covering this that I glossed over reading the spec?
>> > If it's not just something I missed, is this worth clarifying in the spec,
>> > without changing the behavior (purely a documentation change)?
>>
>> This is expressed in the EBNF grammar in the language spec.  x[0] is a
>> PrimaryExpr.  *x[0] is a unary_op applied to a PrimaryExpr.
>>
>> Ian
>
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