Thank you all! But I still don't quite understand why the rule does not apply to the first case?
var a2 u = a1 x ---> a1 T ---> u V ---> uint64 V and T has the identical underlying types (ie, uint64) and V is not a named type (literal) . which part did I misunderstand? On Wednesday, July 5, 2017 at 3:26:13 PM UTC+8, Jan Mercl wrote: > > On Wed, Jul 5, 2017 at 9:17 AM Darren Hoo <darre...@gmail.com > <javascript:>> wrote: > > > f1's type is func(int), and f2's type is main.f, they are different > types, does implicit conversion happen here? > > It's not a conversion. The rule is about assignability > <https://golang.org/ref/spec#Assignability>: "x's type V and T have > identical underlying types <https://golang.org/ref/spec#Types> and at > least one of V or T is not a named type > <https://golang.org/ref/spec#Types>." > > -- > > -j > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
