but
const (
a = iota
b
s string
d
)
is not a valid declaration. You can't say "the rule is the same for
constants".
Again: const-declarations and variable declarations are very different. You
can not argue "it's the same"; it's not.
On Wed, May 3, 2017 at 6:28 PM, T L <tapir....@gmail.com> wrote:
>
>
> On Thursday, May 4, 2017 at 12:17:13 AM UTC+8, Jan Mercl wrote:
>>
>> On Wed, May 3, 2017 at 6:00 PM T L <tapi...@gmail.com> wrote:
>>
>> > Just like what expected for constants.
>>
>> For constants it's expected to reuse the last iota expression when
>> absent. Do you propose that
>>
>> var (
>> a = iota
>> b
>> )
>>
>> will become valid and initialize a to 0 and b to 1?
>>
>> If so, is it valid and what shall happen when one writes
>>
>> var (
>> a = iota
>> b
>> s string
>> d
>> )
>>
>> ?
>>
>
> The rule is same for constants: d is also string, as s.
>
>
>
>>
>> If it's not valid, why?
>>
>>
>> --
>>
>> -j
>>
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