It does not do this.

It would be nice in most cases if it did.

But some times extra parenthesis are useful for making some formula
easier to read.


Janne Snabb
sn...@epipe.com

On 2017-04-15 01:36, Jesper Louis Andersen wrote:
> If I remember correctly, you can just go wild and put in all the
> parenthesis you want and "go fmt" will clean it up for you wrt
> precedence rules
> 
> 
> On Fri, Apr 14, 2017, 14:38 Elias Naur <elias.n...@gmail.com
> <mailto:elias.n...@gmail.com>> wrote:
> 
>     Your expression is (effectively) ((z*z-x)/2)*z. Use parentheses to
>     group the 2*z term: (z*z-x)/(2*z).
> 
>       - elias
> 
> 
>     On Friday, April 14, 2017 at 2:30:33 PM UTC+2, ksam...@redhat.com
>     <mailto:ksam...@redhat.com> wrote:
> 
>         Hello,
> 
>         Am a newbie to golang, and was trying myself with golang tour. 
> 
> 
>         I was trying https://tour.golang.org/flowcontrol/8 and below is
>         my code snippet for the same 
> 
>         |
>         package main
> 
>         import (
>         "fmt"
>         "math"
>         )
> 
>         func Sqrt(x float64) float64 {
>         z := float64(1)
> 
>         for i := 0; i < 10; i++ {
>         //z = z - (z*z-x)/2*z -- this does not work why ???
>         z = z - (float64(z*z)-float64(x))/float64(2*z)
>         }
>         return float64(z)
>         }
> 
>         func main() {
>         fmt.Printf("Ans: %0.2f \n", Sqrt(4))
>         fmt.Printf("math.Sqrt: %0.2f", math.Sqrt(4))
>         }
> 
>         |
> 
>         I assume that all data is handled as float64 only, if you see
>         the commented codes not seem to work especially for simple
>         Sqrt(4) i get an answer of 1.76 instead of 2 ;) .. but after i
>         did the casting to float64(..) it seem to work right.. 
> 
>         I am not able to understand why .. 
> 
>         any thoughts ?
> 
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