This gets you https://play.golang.org/p/J8hFZyyFF8 about 25% perf boost:
BenchmarkDecode-8 30000 43268 ns/op BenchmarkUnmarshal-8 30000 43195 ns/op BenchmarkManual-8 50000 30216 ns/op Also, Decode/Unmarshal seem pretty equal. If you don't need full xml spec, then you probably can implement a faster parser. (Maybe one already exists https://godoc.org/?q=xml) And... if you can avoid XML for this, then avoid it. It's not ideal for this. + Egon On Wednesday, 8 February 2017 07:22:35 UTC+2, emarti...@gmail.com wrote: > > Hello, > > I'm making a go code which is basically parsing a lot of small xml > responses. I've noticed that right after I enable the parsing code, my R/S > as per wrk, as well as response times drop to 15% for some reason. I'm > testing with about 2000 concurrent clients and each one parses about 50 > very small xmls (1 entry each). > > Below is my code, does anyone have any experience/feedback with xml > decoding performance on go? > > > package main > > > import ( > "encoding/xml" > "bytes" > ) > > > type DBXML struct{ > HostProperties DBXML_HostProperties > Listing DBXML_Listing > } > > type DBXML_Listing struct { > sid string > Original_title string `xml:"title"` > Original_desc string `xml:"desc"` > Original_domain string `xml:"display_url"` > Original_bid float64 `xml:"bid"` > Original_URL string `xml:"clickurl"` > } > > type DBXML_HostProperties struct { > Tags []DBXML_Listing `xml:"record"` > } > > func (r *DBXML ) parse_response (data []byte) bool { > reader := bytes.NewReader(data) > decoder := xml.NewDecoder(reader) > decoder.Decode(&r.HostProperties); > > //xml.Unmarshal(data, &r.HostProperties) // With this one i got even > less performance. > > } > > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
