In go when closure call the out varible will pass pointer to the closure
func so I doubt in example2.go y is passed &y to closure
I don't know the compile how to analysis this and decide that can be
allocated in stack correctly ?
在 2016年10月4日星期二 UTC+8下午11:54:02，Chris Manghane写道：
>
> In example1, the // BAD: y escapes is there because y should not escape
> from that function, but the current algorithm needs to be improved for this
> case. In that closure, the address of y is captured as the closure argument
> p and since p is only dereferenced, the analysis should not consider it to
> escape.
>
> In example3, the analysis above applies and y should not escape. y is
> closed over and dereferenced, but we correctly do not mark it as escaping.
>
> In example2, y contains no pointers; it can never escape. The test was to
> see if capturing/closing over a non-pointer value would cause it to escape.
>
> It's a bit confusing, but to restate, in example1, y should not escape
> even though it currently does.
>
> On Mon, Oct 3, 2016 at 11:09 PM, 刘桂祥 <liuguix...@gmail.com <javascript:>>
> wrote:
>
>> // example1.go
>>
>> package main
>>
>>
>> func main() {
>> var y int // BAD: y escapes
>> func(p *int, x int) {
>> *p = x
>> }(&y, 42)
>> }
>>
>> example1.go y escape to the heap
>>
>> // example2.go
>>
>> package main
>>
>> func main() {
>> var y int
>> func(x int) {
>> y = x
>> }(42)
>> }
>>
>> example2.go y is not escaped and why ??
>>
>> // example3.go
>>
>> package main
>>
>> func main() {
>> a := 100
>> y := &a
>> func(x int) {
>> *y = x
>> }(42)
>> }
>>
>> example3.go y is not escaped and why ??
>>
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