A rune is just an alias for int32. So when you are printing r, you are
printing a int32 number.
s is a string. So when you print it, you get the expected output ("a").
Em seg, 22 de ago de 2016 às 12:51, JC <mr.jamie.caldw...@gmail.com>
escreveu:
> Dear gophers,
>
> I'd appreciate some help.
>
> Given:
>
> func main() {
> r := 'a'
> s := "a"
> fmt.Println(r)
> fmt.Println(s)
> }
>
> My very possibly incorrect understanding is that the rune r holds a
> Unicode code-point encoded with UTF-8 and stored as integer value, in this
> case 97, as type int32. s is of type string, and contains a code-point
> encoded by UTF-8, but which will be stored in a slice of type byte (which
> will use just one uint8 in this case). Assuming that is all correct,
> then my questions are:
>
> 1. Will the rune / any rune always use 32 bits?
> 2. Why does printing r output the integer value, but printing s yield the
> code-point itself?
>
> Cheers for your help.
> JC.
>
>
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