[go-nuts] parse.ParseExpr("var a = 9") returns error "expected operand, found 'var'"

[Jason E. Aten]

I'm trying to use parser.ParseExpr. I'm thinking "var a = 9" is a valid 
expression, but ParseExpr returns an error:

// simple.go:

package main


import (

    "fmt"

    "go/parser"

)


func main() {

    ast0, err := parser.ParseExpr("var a = 9")

    fmt.Printf("err = %v\n", err)

    fmt.Printf("ast0 = %#v\n", ast0)

}


$go run simple.go

*err = 1**:**1**: *expected operand, found 'var'

ast0 = <nil>

$


Pedantically, perhaps this is a statement rather than an expression. That 
begs the question, is there anyway to parse single statements (using 
go/parse)?

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