Le lundi 4 juillet 2016 02:25:06 UTC, Jingguo Yao a écrit :
>
> Take the following code as an example:
>
>
> package main
> import (
> "fmt"
> )
> const (
> First int64 = iota
> Second
> )
> const (
> One int64 = 1
> Two = 2
> )
> func main() {
> fmt.Printf("First type: %T, Second type: %T\n", First, Second)
> fmt.Printf("One type: %T, Two type: %T\n", One, Two)
> }
>
>
> Running the above code produces:
>
>
> First type: int64, Second type: int64
> One type: int64, Two type: int
>
>
> Why is Second's type int64 instead of the default type int like Two? I
> think
> that it is decided by the following rule from
> https://golang.org/ref/spec#Constant_declarations. Is my understanding
> correct?
>
>
> > Within a parenthesized const declaration list the expression list
> > may be omitted from any but the first declaration. Such an empty
> > list is equivalent to the textual substitution of the first
> > preceding non-empty expression list and its type if any. Omitting
> > the list of expressions is therefore equivalent to repeating the
> > previous list. The number of identifiers must be equal to the number
> > of expressions in the previous list.
>
>
>
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