Hauke Laging <mailinglis...@hauke-laging.de> writes: > Am Montag 21 März 2011 06:48:07 schrieb Jerome Baum: > >> 2. If I encrypt to only myself, this is revealed. > > How?
Only one recipient. Remember I use encrypt-to-self. -- PGP: A0E4 B2D4 94E6 20EE 85BA E45B 63E4 2BD8 C58C 753A PGP: 2C23 EBFF DF1A 840D 2351 F5F5 F25B A03F 2152 36DA
pgppLFTmagoeS.pgp
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