On Tue, Feb 07, 2006 at 08:14:29PM +0100, Ludwig H?gelsch?fer wrote: > Hi, > > On 07.02.2006 20:05 Uhr, Oskar L. wrote: > > > This is of course only true if the attacker knows it is exactly 15 > > characters long. If not, then it should be calculated like this: 95^1 + > > 95^2 + 95^3 + ... + 95^15. > > Right, this gives exactly 95^16 - 1.
Errr... only for very small values of 95, I'd say ;) Namely, only if 95 equals 2... which it doesn't quite seem to :) Oh, ooookay, so it's more like (95^16 - 1^16) / (95 - 1), which is only 94 times less than your bid. But still... :) > This is not a dramatic improvement compared to 2^256. Errrrrr... what?! Straight from bc's mouth: (95^16-1)/(95-1) 468219860267835848675991626496 2^256 115792089237316195423570985008687907853269984665640564039457584007913129639936 Okay, so it might not be quite in the feasible range - I'll leave that for others to judge - but it does seem pretty dramatic to me. G'luck, Peter -- Peter Pentchev [EMAIL PROTECTED] [EMAIL PROTECTED] [EMAIL PROTECTED] PGP key: http://people.FreeBSD.org/~roam/roam.key.asc Key fingerprint FDBA FD79 C26F 3C51 C95E DF9E ED18 B68D 1619 4553 If I had finished this sentence,
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