Don't forget you have to remove the `<?xml version=....?>` part of the XML
before it will parse properly:
content = Shell.get_file_contents_utf8_sync('/path/to/file'); // or
your preferred file-reading function
// remove <?xml version=...?> (developer.mozilla.org/en-US/docs/E4X)
content =
content.replace(/^<\?xml\s+version\s*=\s*(["']).*?\1[^?]*\?>/, '');
xml = new XML(content);
Then you can do stuff like `xml.tagname` to get a list of children with
that tag name (use `xml.tagname.length()` to get the number of nodes,
`xml.tagname[i]` to iterate through).
You can also use double dot `xml..tagname` to find any descendant with
'tagname', not just the immediate children.
And `xml.tagname.@attributename` (e.g. xml.a.@href) to retrieve that
attribute.
But when you do that the output is not a string - you need to use
xml.a.@href.toString() to convert it.
To get the text of a tag (e.g. <a href=...>Link Text</a>) you can use
`node.text()`.
On 9 November 2012 00:35, Jasper St. Pierre <jstpie...@mecheye.net> wrote:
> You can use E4X to parse XML. It's a fancy language thing that's a bit
> hard to get used to, and it's deprecated, but it works.
>
> https://developer.mozilla.org/en-US/docs/E4X
>
>
> On Thu, Nov 8, 2012 at 7:12 AM, alok barsode <alokbars...@gmail.com>wrote:
>
>> Hi,
>>
>> I am writing a gnome shell extension for oFono.
>> I need to know a way to parse an XML file in the extension.
>>
>>
>> I am using gnome-shell 3.4
>>
>> Thanks,
>> Alok.
>>
>> _______________________________________________
>> gnome-shell-list mailing list
>> gnome-shell-list@gnome.org
>> https://mail.gnome.org/mailman/listinfo/gnome-shell-list
>>
>>
>
>
> --
> Jasper
>
>
> _______________________________________________
> gnome-shell-list mailing list
> gnome-shell-list@gnome.org
> https://mail.gnome.org/mailman/listinfo/gnome-shell-list
>
>
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