Hi Thomas,

thank you for your reply.

Hi Mike,

Your confusion might stem from a very simple issue.
To see the overlap of the forward and backward distributions,
you have to plot

 N(+Delta H(lambda=x) | lambda=y) and
 N(-Delta H(lambda=y) | lambda=x).

Do I understand it right, that for instance (consider lambda step = 0.5) ONLY N(+Delta H(lambda=0) | lambda=0.5) AND N(-Delta H(lambda=0.5) | lambda=0)
has to overlap, and then
N(+Delta H(lambda=0.5) | lambda=1) AND N(-Delta H(lambda=1) | lambda=0.5) has to overlap, to get an accurate estimation of the free energy difference, and not (essentially) other distributions? An example would really help me out of my confusion :(


That is, you have to plot the histogram for the negative of the energy difference samples in the backward direction.

And is it right, that N(-Delta H(lambda=y) | lambda=x) equals N(+Delta H(lambda=y) | lambda=x) if I
simply mirror the distribution at the y-axis?

See also the original paper of Charles Bennett for an explanation of the overlap and how it is measured.

I read the original paper a couple of times, and I understand, that the squared value of the standard deviation (eq 11) measures the overlap. And according to Fig.5, I understand, that the (complementary) fermi functions have to show an overlap and that in principle the method calculates the perturbation between A -> B via a shifted state by a constant C in between. But I cannot bring it to the context of the g_bar output
    N( Delta H(lambda=x) | lambda=y).

How are the fermi functions and the constant C related to N( Delta H(lambda=x) | lambda=y) in detail? Or did I miss the definition in Bennett's paper, where is said, which distributions in detail have to overlap and how they are defined?

Best,
Thomas.

---------------------------------------------------------------------------------
R. Thomas Ullmann, PhD
Theoretical & Computational Biophysics
Max Planck Institute for Biophysical Chemistry
Am Fassberg 11
Göttingen, Germany
thomas.ullm...@mpibpc.mpg.de
www.bisb.uni-bayreuth.de/People/ullmannt
---------------------------------------------------------------------------------


Thank you for any help,

  Mike
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