I tried using the nonbonded parameters as defined below in my ffoplsaanb.itp file for methanol in water and this is the syntax I used:

[nonbond_params ]
;i      j       func    c6      c12
  opls_154    opls_111  1       0.00E+000       2.43E-006
  opls_154    opls_112  1       0.00E+000       0.00E+000
  opls_154    opls_112  1       0.00E+000       0.00E+000
  opls_155    opls_111  1       0.00E+000       0.00E+000
  opls_155    opls_112  1       0.00E+000       0.00E+000
  opls_155    opls_112  1       0.00E+000       0.00E+000
  opls_156    opls_111  1       0.00E+000       2.70E-007
  opls_156    opls_112  1       0.00E+000       0.00E+000
  opls_156    opls_112  1       0.00E+000       0.00E+000
  opls_157    opls_111  1       0.00E+000       3.01E-006
  opls_157    opls_112  1       0.00E+000       0.00E+000

When I tried to do mdrun, I got an error saying my system is exploding. I tried doing the mdrun without nonbonded parameters and it runs fine. So I am not sure if I am using the nonbond_params concept correctly. i.e. I want C6 to be zero between my solute (methanol) and solvent (water). This is the error:

Warning: 1-4 interaction between 2 and 6 at distance 3.786 which is larger than the 1-4 table size 2.500 nm
These are ignored for the rest of the simulation
This usually means your system is exploding,
if not, you should increase table-extension in your mdp file
or with user tables increase the table size

Suggestions?

Thanks.

-Nisha P

Quoting [email protected]:

Okay I am going to give it a try. I just wanted to make sure I was
calculating C6 and C12 correctly as well using sigma and epsilon
according to rule 3

C12 = Sigma^(6)*C6
C6 = 4*sigma^(6)*epsilon

Thanks


Quoting "Justin A. Lemkul" <[email protected]>:



[email protected] wrote:
Hello,

I have a concern regarding C6 attractive term in LJ potential. I am using OPLS-AA force field, and I wish to turn off attractive term C6 by setting the parameters to zero. One of the suggestion was to add a [nonbond_params] in my ffoplsaanb.itp file and set the C6 to zero between the non-bonded pair. In my system for example, which consists of one methanol in water, I wish to set C6 term to zero between my solute and solvent. Since OPLSAA is all atom force field it treats each atom individually and has sigma and epsilon for each atom, so I am not sure how I would actually set my nonbond_params in my nb.itp file. I realize I need to convert each sigma and epsilon to C6 and C12, so say for example for methanol in water my [nonbond_params] would look something like this?

[ nonbond_params ]
; i    j func          c6           c12
    CT        OW  1   0.00      calculated value for C12 here?
    CT        HW1  1  0.00
    CT        HW2  1  0.00

CT is the carbon in Methanol. OW, HW1 an HW2 correspond to atoms in TIP3P water model

Is that correct? Would I have to do that for each atom in methanol?


Sounds about right to me.

-Justin

Any suggestions would be appreciated.

Thanks.

Nisha P


--
========================================

Justin A. Lemkul
Ph.D. Candidate
ICTAS Doctoral Scholar
MILES-IGERT Trainee
Department of Biochemistry
Virginia Tech
Blacksburg, VA
jalemkul[at]vt.edu | (540) 231-9080
http://www.bevanlab.biochem.vt.edu/Pages/Personal/justin

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