Hi Tsjerk,

The system I am working on is the C-terminal tails of tubulin. The structure of the tails is missing in all of the crystal structures of tubulin, likely due to the flexibility of the tails. Since tubulin is quite large, a heterodimer of almost 900 residues, it is not really possible for us to adequately sample the tails' configuration space by simulating the whole protein. What we have done is to simulate nine different isotypes of the c-terminal tail fragment (9-26 residues) using constant pressure REMD.

Among the properties we are interested in is quantifying and comparing the flexibility of tails from the different isotypes. I have performed PCA twice on this; fitting the all the C-alphas and then the backbone atoms of the first three residues to a reference structure. The motivation for the later fitting procedure is that the fragments would be anchored to tubulin at the fragments N- terminus. This is to look at how the fragments behave in the absence of tubulin's potential but as if they are still anchored. When performing the PCA we are fitting to a reference structure but still using the deviations from the mean and not from the reference structure. To compare the flexibility between the isotypes we had hoped to normalize the eigenvalues.

I did note that I was inadvertently using the deviation from the reference structure rather than from the mean (-ref). Is this what you meant by a non-central covariance matrix? Using the deviation from the mean I obtained standard deviations more inline with what I originally expected. These are 0.8 nm at most if I normalize the variance by the number of atoms.

My two questions are then:

1) does it make sense to fit the last three residues, as I described above, for the purposes of PCA?

2) is it possible to compare the relative flexibilities of the fragments using PCA?

Thank you,

Tyler

Hi Tyler,

First, what question are you trying to answer? You're different peptides
have completely different conformational spaces, simply because of the
differences in degrees of freedom, so you can't compare the PCA results from
one system with the other. That is, unless you pick a subset from each
system, consisting of comparable particles, for which you can safely make
the assumption that under equal circumstances should give the same
eigenvectors and -values. From that assumption, you could try to make an
assessment whether the behaviour between the systems is different.

Also, since you're using only the first three residues for fitting, you generate a non-central covariance matrix. That would be useful if you would
like to exaggerate certain motional features, right, but it makes the
interpretation of PCA results difficult. If it's for the purpose of
comparing things, I wouldn't go there if I were you. The non- centrality is
also the reason that your standard deviations end up high. You're not
subtracting the mean so your standard deviations is sqrt( sum(x^2)/N )
rather than sqrt( sum((x-average)^2))/N ). Is this really what you want to do? What are you expecting to get from this? I'd like to know the question your trying to answer and your assumptions on the nature of the data...

Cheers,

Tsjerk

On 4/7/06, Tyler Luchko <[EMAIL PROTECTED]> wrote:

Hello,

Thank you for the previous responses.  I still have some questions
about the eigenvalues however.

I should note that the frames of my trajectory have been fit to a
reference structure using the backbone atoms of the first three
residues.  This is because the peptide is a fragment of a much larger
protein.

1) If I wish to compare the eigenvalues of several peptides of
different lengths how would I normalize the eigenvalues?  Do I simply
divide by the number of atoms used in the calculation?

2) If the eigenvalue represents the sum of the variances for each
particle along the eigenvector then dividing the eigenvector by the
number of atoms used in the calculation should be the average
variance. Likewise, the square root of this should be the average
standard deviation per atom.  In my case, the first eigenvector is a
stretching in the length of the peptide.  Shouldn't the average
standard deviation per atom along this stretching motion be smaller
that the standard deviation in the length of the entire peptide, or
at least smaller than the extended length of the peptide?

Thank you,

Tyler

Hi Tyler,

Note that the eigenvalue represents the sum of the variances for each
particle along the associated eigenvector. That seems quite
reasonable to
me.

Tsjerk

On 4/6/06, Tyler Luchko <[EMAIL PROTECTED]> wrote:

Hello,

I have performed PCA analysis, without mass weighting, on a peptide
using g_covar and g_anaeig. The first principal component generally corresponds to the stretching of the peptide. I understand that each eigenvalue represents the variance in the motion along the associated eigenvector. However, the square root of the variance for the first eigenvalue is ~20 nm while the maximum extended length of any peptide is ~3 nm. I have tried normalizing the eigenvalues by the number of
atoms used for the analysis (73) but this gives the standard
deviation of the motion to be ~2.2 nm, still much too large. I would
like to know how to normalize the eigenvalues to obtain reasonable
standard deviations from the eigenvalues.

Thank you,

Tyler


  ________________________________________________________________
(_    Tyler Luchko                           Ph.D. Candidate    _)
  _)   Department of Physics            University of Alberta   (_
(_    Edmonton, Alberta, Canada                                 _)
  _)   780-492-1063                       [EMAIL PROTECTED]   (_
(________________________________________________________________)



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--

Tsjerk A. Wassenaar, M.Sc.
Groningen Biomolecular Sciences and Biotechnology Institute (GBB)
Dept. of Biophysical Chemistry
University of Groningen
Nijenborgh 4
9747AG Groningen, The Netherlands
+31 50 363 4336
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Tsjerk A. Wassenaar, M.Sc.
Groningen Biomolecular Sciences and Biotechnology Institute (GBB)
Dept. of Biophysical Chemistry
University of Groningen
Nijenborgh 4
9747AG Groningen, The Netherlands
+31 50 363 4336

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