On Tue, Jun 02, 2015 at 11:10:22PM +0200, Michael Haggerty wrote:

> >> +
> >> +                       if (!(flag & REF_ISBROKEN) && is_null_sha1(sha1)) {
> > 
> > Why do we do the extra check for !(flag & REF_ISBROKEN) here?
> 
> That was an attempt to avoid calling is_null_sha1() unnecessarily. I
> think I can make this go away and make the code clearer in general by
> restructuring the logic a little bit. I will do that in the next round.

If you get rid of the useless hashclr(), then this just becomes:

  if (!(flag & REF_ISBROKEN) && is_null_sha1(sha1))
        flag |= REF_ISBROKEN;

The reason for the initial check seems pretty obvious then (but it would
also be OK without it; is_null_sha1 is not that expensive).

-Peff
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