On Mar 15, Johannes Sixt wrote:
> > -   echo "$@" | sed -e 's/^/#       /'
> > +   printf '%s\n' "$@" | sed -e 's/^/#      /'
> 
> This should be
> 
>       printf '%s\n' "$*" | sed -e 's/^/#      /'

Right, that should be $* to always be one argument for the format
pattern.

Thanks

Uwe
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