[RFC/PATCH 4/5] fetch: make the code more understandable

[Felipe Contreras]

The comment makes it seem as if the condition is the other way around.
The exception is when the oid is null, so check for that.

Signed-off-by: Felipe Contreras <felipe.contre...@gmail.com>
---
 builtin/fetch.c | 16 +++++++++-------
 1 file changed, 9 insertions(+), 7 deletions(-)

diff --git a/builtin/fetch.c b/builtin/fetch.c
index 8af5e319f1..9dc551551e 100644
--- a/builtin/fetch.c
+++ b/builtin/fetch.c
@@ -367,19 +367,21 @@ static void find_non_local_tags(const struct ref *refs,
         */
        for_each_string_list_item(remote_ref_item, &remote_refs_list) {
                const char *refname = remote_ref_item->string;
+               struct ref *rm;
 
                item = hashmap_get_from_hash(&remote_refs, strhash(refname), 
refname);
                if (!item)
                        BUG("unseen remote ref?");
 
                /* Unless we have already decided to ignore this item... */
-               if (!is_null_oid(&item->oid)) {
-                       struct ref *rm = alloc_ref(item->refname);
-                       rm->peer_ref = alloc_ref(item->refname);
-                       oidcpy(&rm->old_oid, &item->oid);
-                       **tail = rm;
-                       *tail = &rm->next;
-               }
+               if (is_null_oid(&item->oid))
+                       continue;
+
+               rm = alloc_ref(item->refname);
+               rm->peer_ref = alloc_ref(item->refname);
+               oidcpy(&rm->old_oid, &item->oid);
+               **tail = rm;
+               *tail = &rm->next;
        }
        hashmap_free(&remote_refs, 1);
        string_list_clear(&remote_refs_list, 0);
-- 
2.21.0