Stephan Beyer <s-be...@gmx.net> writes:
> It was possible to invoke "git bisect run" without any command.
> This considers all commits as good commits since "$@"'s return
> value for empty $@ is 0.
>
> This is most probably not what a user wants (otherwise she would
> invoke "git bisect run true"), so not providing a command now
> results in an error.
>
> Signed-off-by: Stephan Beyer <s-be...@gmx.net>
> ---
Makes sense to me. Thanks, will queue.
> git-bisect.sh | 2 ++
> 1 file changed, 2 insertions(+)
>
> diff --git a/git-bisect.sh b/git-bisect.sh
> index 0138a8860..a69e43656 100755
> --- a/git-bisect.sh
> +++ b/git-bisect.sh
> @@ -450,6 +450,8 @@ bisect_replay () {
> bisect_run () {
> bisect_next_check fail
>
> + test -n "$*" || die "$(gettext "bisect run failed: no command
> provided.")"
> +
> while true
> do
> command="$@"
