On Fri, Oct 13, 2017 at 01:35:22PM -0400, Jeff King wrote:
> On Fri, Oct 13, 2017 at 11:58:12AM +0900, 小川恭史 wrote:
> 
> You can also just do:
> 
>   for i in 1 2 3; do
>      git stash drop $i
>   done
> 

Doesn't stash 2 become stash 1 after the first drop, and the same for 3,
resulting in dropping stash 1, 3 and 5?

So something like

  for i in 3 2 1; do
      git stash drop $i;
  done

Or leave $i out altogether.

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