On Wed, Jan 23, 2019 at 9:05 AM Paul Colquhoun <paul...@andor.dropbear.id.au> wrote: > > On Wednesday, 23 January 2019 5:52:57 PM AEDT Alexander Kapshuk wrote: > > On Wed, Jan 23, 2019 at 5:20 AM Adam Carter <adamcart...@gmail.com> wrote: > > >> > François-Xavier > > >> > > >> My bad, it should be: > > >> > > >> sed 's/0*\([0-9][0-9]*\)/\1/g' > > >> > > >> (tests are indeed needed!) > > > > > > Many thanks François. This is almost right, but it is also stripping zeros > > > that follow a letter, and I only want it to strip zeros that are > > > proceeded by a period. There are no leading zeros in the first octet of > > > the IP so that case does not need to be handled. > > > > > > Does the \1 refer to what's in the ()'s? So anything that one would wont > > > to carry through should be inside the ()'s and anything that's outside is > > > stripped, right? > > Would something like to do the trick? > > echo 198.088.062.01 | sed 's/\.0/./g' > > 198.88.62.1 > > In a word, no. > > echo 198.088.0.01 | sed 's/\.0/./g' > 198.88..1 > > > -- > Reverend Paul Colquhoun, ULC. http://andor.dropbear.id.au/ > Asking for technical help in newsgroups? Read this first: > http://catb.org/~esr/faqs/smart-questions.html#intro > > > >
How about this one? echo '198.088.0.01 198.088.062.01' | sed 's/\.0\([0-9][0-9]*\)/.\1/g' 198.88.0.1 198.88.62.1
