Hello,
On Mon, 21 Jan 2019, Michael Orlitzky wrote:
>On 1/21/19 6:50 PM, Adam Carter wrote:
>> I need to clean up a file which has IP addresses with leading zeros in
>> some of the octets so I need to make, say, .09 into .9
>>
>> How do i do that in sed/awk/whatever?
>
>The first thing you should do is construct a bunch of test cases, with all of
>the possible input representations and what you think the output
>representation should be. Then, you should write a program in something other
>than bash that passes all of the test cases. It's not as easy as it sounds;
>for example:
>
> * What happens to 0.1.2.3?
>
> * What happens to 01.2.3.4?
>
> * What happens to 1.2.3.0?
>
> * What happens to 1.2.000.3?
>
>You need a parser, not a regular expression. (You can do it with a regex, but
>it's going to be one of those comical twelve-page-long things.)
$ printf '0.1.2.3 01.2.3.4 1.2.3.0 1.2.000.3\n' | \
sed 's/0*\([[:digit:]]\+\)/\1/g'
0.1.2.3 1.2.3.4 1.2.3.0 1.2.0.3
HTH,
-dnh
--
printk(KERN_DEBUG "adintr: Why?\n");
linux-2.6.19/sound/oss/ad1848.c
