Hi,
> 2) I was using a simple example:
>
> #pragma unroll 2
> for (i=0;i<6;i++)
> {
> printf ("Hello world\n");
> }
>
> If I do this, instead of transforming the code into :
> for (i=0;i<3;i++)
> {
> printf ("Hello world\n");
> printf ("Hello world\n");
> }
>
> as we could expect, it is transformed into:
> for (i=0;i<2;i++)
> {
> printf ("Hello world\n");
> printf ("Hello world\n");
> }
> for (i=0;i<2;i++)
> {
> printf ("Hello world\n");
> }
>
>
> (I am using 4.3.2 currently)
>
> I am using the tree_unroll_loop function to perform the unrolling and
> it seems to always want to keep that epilogue. Is there a reason for
> this? Or is this a bug of some sorts?
such an epilogue is needed when the # of iterations is not known in the
compile time; it should be fairly easy to modify the unrolling not to
emit it when it is not necessary,
Zdenek
