Hi,
in this rejects-valid, as part of build_user_type_conversion_1,
standard_conversion is called by implicit_conversion with a *null* expr,
thus the condition in standard_conversion
/* [conv.ptr]
A null pointer constant can be converted to a pointer type; ... A
null pointer constant of integral type can be converted to an
rvalue of type std::nullptr_t. */
if ((tcode == POINTER_TYPE || TYPE_PTRMEM_P (to)
|| NULLPTR_TYPE_P (to))
&& expr && null_ptr_cst_p (expr))
conv = build_conv (ck_std, to, conv);
is false and the snippet is rejected. Should we pass a nullptr_node as
expr in such cases, ie, when handling conversions functions returning
std::nullptr_t?!? The below passes testing.
Thanks,
Paolo.
//////////////////////
Index: cp/call.c
===================================================================
--- cp/call.c (revision 218022)
+++ cp/call.c (working copy)
@@ -3685,7 +3685,8 @@ build_user_type_conversion_1 (tree totype, tree ex
conversion *ics
= implicit_conversion (totype,
rettype,
- 0,
+ NULLPTR_TYPE_P (rettype)
+ ? nullptr_node : NULL_TREE,
/*c_cast_p=*/false, convflags,
complain);
Index: testsuite/g++.dg/cpp0x/nullptr33.C
===================================================================
--- testsuite/g++.dg/cpp0x/nullptr33.C (revision 0)
+++ testsuite/g++.dg/cpp0x/nullptr33.C (working copy)
@@ -0,0 +1,19 @@
+// PR c++/63757
+// { dg-do compile { target c++11 } }
+
+typedef decltype(nullptr) nullptr_t;
+
+void bar(void*) {}
+
+struct foo
+{
+ operator nullptr_t()
+ {
+ return nullptr;
+ }
+};
+
+int main()
+{
+ bar(foo());
+}