On Mon, Sep 16, 2013 at 10:29:37AM +0100, James Greenhalgh wrote:
> The little endian compiler would lay memory out as:
>
> 0x0 ... 0x8
> | 0b | 0a | 1b | 1a | 2b | 2a | 3b | 3a |
>
> And the big endian compiler would lay out memory as:
>
> 0x0 ... 0x8
> | 0a | 0b | 1a | 1b | 2a | 2b | 3a | 3b |
>
> In both cases, element 0 is '0x0a0b'. If we load this array as a
> vector with ld1.h both big and little-endian compilers will load
> the vector as:
>
> bit 128 .. bit 64 bit 0
> lane 16 | lane 3 | | lane 0 |
> |..... | 3b | 3a | 2b | 2a | 1b | 1a | 0b | 0a |
>
Ugh, I knew I would make a mistake somewhere!
This should, of course, be loaded as:
bit 128 .. bit 64 bit 0
lane 16 | lane 3 | | lane 0 |
|..... | 3a | 3b | 2a | 2b | 1a | 1b | 0a | 0b |
James
