On 06/27/2013 04:56 PM, Andrew Sutton wrote:
I was not aware of that. That's probably the right, but I remember having some troubles getting that to work the way I wanted in the previous implementation. It seemed like I actually had to evaluate the expression to determine if it was actually constexpr.
Right; an expression is a constant-expression iff it evaluates to a constant value. Without evaluating the expression we can't catch things like division by zero which prevent it from being a constant-expression.
Jason