On Tue, 26 Nov 2024, Jonathan Wakely wrote:
In the bla() example above, the call bla() is a constant expression
when used to initialize a const int, so the compiler is required to
evaluate it at compile time.
When used in contexts that doesn't require an integral constant I think a
distinction between evaluating at compile time or at run time can't be
observed.
Agreed.
Can't be observed might be a bit strong?
constexpr int f(){
if consteval {return 1;} else {return 2;}
}
int main(){
int a=f();
const int b=f();
return a+b;
}
returns 3 (and clang agrees).
--
Marc Glisse
