Hi,
With -O3 -fsignaling-nans -fno-signed-zeros, compiler should not simplify 'x + 0.0' to 'x'. GCC Bugzilla : Bug 110305 gcc/ChangeLog: 2023-06-19 Toru Kisuki <tkis...@tachyum.com> * simplify-rtx.cc (simplify_context::simplify_binary_operation_1): --- gcc/simplify-rtx.cc | 3 ++- 1 file changed, 2 insertions(+), 1 deletion(-) diff --git a/gcc/simplify-rtx.cc b/gcc/simplify-rtx.cc index e152918b0f1..cc96b36ad4e 100644 --- a/gcc/simplify-rtx.cc +++ b/gcc/simplify-rtx.cc @@ -2698,7 +2698,8 @@ simplify_context::simplify_binary_operation_1 (rtx_code code, when x is NaN, infinite, or finite and nonzero. They aren't when x is -0 and the rounding mode is not towards -infinity, since (-0) + 0 is then 0. */ - if (!HONOR_SIGNED_ZEROS (mode) && trueop1 == CONST0_RTX (mode)) + if (!HONOR_SIGNED_ZEROS (mode) && !HONOR_SNANS (mode) + && trueop1 == CONST0_RTX (mode)) return op0; /* ((-a) + b) -> (b - a) and similarly for (a + (-b)). These -- 2.38.1